Initially, a 1.50-liter compressible container of 0.35 moles of a gas exerts a pressure of 740 millimeters of mercury at a temperature of 275 Kelvin. What is the pressure when the container is compressed to 0.50 liters, the moles of gas reduces to 0.20 moles, and the temperature changes to 32 degrees Celsius?

Question

anonymous · Answer

Use ideal gas equation : PV=nRT 
Pressure*volume=moles*R ideal gasconstant*temperatue..

anonymous · Answer

P1V1/n1T1 = P2V2/n2T2.............find P2 by putting all values in correct order