What are the exact solutions of x2 + 3x + 1 = 0?
a. x = the quantity of 3 plus or minus the square root of 13 all over 2 b. x = the quantity of negative 3 plus or minus the square root of 13 all over 2 c. x = the quantity of 3 plus or minus the square root of 5 all over 2 d. x = the quantity of negative 3 plus or minus the square root of 5 all over 2
use quadratic formula
Okay
\[\frac{ -b \pm \sqrt{-b-4(a)(c)} }{ 2a}\] where \[a ^{2}+b+c=0\]
Which one's a b and c?
Your equation is \[x ^{2}+3x+1\] So your values would be a = 1 b =3 c=1 Plug in and solve
Correction to my quadratic formula for to square the b inside the square root
\[\frac{ -b \pm \sqrt{-b ^{2}-4(a)(c)} }{ 2(a) }\] sorry bout that
thats okay
-3+/- sqrt(-3^2-4)/2
-3+/- sqrt(13)/2
so that's the answer?
\[\frac{ -3\pm \sqrt{-3^{2}-4} }{2}\] Solve under the square root
You haven't simplified
I did, its -3 +/ sqrt(13)/2
3 squared is 9 subtract 4 is 5
ohhhh okay
Can you guys help me with a couple other similar questions?
Simply factorize -.- x^2 + 2x + x + 1 = 0 (x+2)(x+1) = 0 x = -1,-2
Thats wrong answer @ilmc1 @Mike546
It's the right answer for the correct equation You used 2x not 3x
What are the exact solutions of x2 + 3x + 1 = 0?
well its either -3+/- sqrt(13)/2 or -3+/- sqrt(5)/2
i wrote 3x = 2x + x
Just look at my answer once more.. :/
This is a multiple choice problem that did not ask for factoring, read @ilmc1 first response it shows you the options.
Ah yes I completely skimmed over that
But what about my answer ?? it cant be wrong if its not given in options
i understand what you are saying.. but i have checked this answer many times
Really? Alright lets go over it we'll see if I am wrong (happens) \[(x^2+2x) (x+1)\]
\[x(x+2) (x+1)\]
There is your simplified form
this is equation, isnt it ? \[x^2 + 3x + 1 = 0\]
OH MY GOD SORRY BRO !! MY BAD pellet @Mike
:)
Nevermind please ! :)
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