Question

http://prntscr.com/1cltdc

explain this!

Answer 1

@shubhamsrg

Answer 2

@tcarroll010

Answer 3

P(h) = P(t) = 0.5

For any event occuring n times, the chance of success r times is given by,

\[C (n,r)= P ^{r} * Q ^{n-r}\]

So, your chance of getting heads up i.e P(h) once, and P(t) twice is,

C(3,2) * (0.5) * (0.5)^2 = 0.375

Answer 4

whats your sample space?

Answer 5

i didn't get this!

Answer 6

i don't know.... :/

Answer 7

sample space means all the possible outcomes you can get

Answer 8

like some of them are
HTT , HTH, TTH, TTT etc
can you mention all ?

Answer 9

@Farheen28 I gave you the formula.. you have to go through that..

See, throwing up three coins simultaneously is like trying out same experiment n times [ n=3 here]

You want heads up once ( i.e. r=1 times success) which automatically implies that remaining two times ( n-r = 3-2 =1 ) times it is going to be tails up..

But you don't know which coin is going to come heads up, either of three may give you that even when your desired outcome exists...

So, there are C(3,2) = 3 ways of getting our desired outcome..

Answer 10

HHHH HTH HTH HTT
TTT THT TTH THH

Answer 11

that is correct.
Now see from sample space tell the number of favorable outcomes? i.e. no. of times exactly 1 head appears

Answer 12

3/8=0.375

Answer 13

(Y)

Answer 14

thanks !