Question

a spring has a spring of 2.0 newtons per meter, how much work must be done to stretch 5.0 meter from its equilubrium position?

Answer 1

To find the work done to further extend it, W = F * d where d is the further extension, and F is the force due to the spring.@whpalmer4 helped me in this problem

Answer 2

thats why im able to answer you

Answer 3

work done by the agent to stretch the spring is its increase in its potential energy.
work done by the agent= change in potential energy of the spring.

Answer 4

The work done on a spring is:
\[w=\frac{ 1 }{ 2 }kx^2\]
Where k=spring constant=2 N/m
And x=distance=5 meters

So the work done in this example, after plugging in, is 25 Nm or 25 J.