Question

Eliminate the parameter.

x = square root of t, y = 3t + 7

y = 3x2 + 7

y = 3square root of x + 7, x ≥ 0

y = 3square root of x - 7, x ≥ 0

y = 3x2 - 7

Answer 1

It should be y= 3x^2+7

Answer 2

can u help me with another one?
@dpasingh

Answer 3

Go ahead

Answer 4

Eliminate the parameter.

x = 4 cos t, y = 4 sin t

Answer 5

Ok pls wait

Answer 6

ok

Answer 7

x = 4 cos t, y = 4 sin t
Squaring each relation separately and then adding them, we find the following
\[i.e. x ^{2} = (4 \cos t)^{2}, y^{2} = (4 \sin t)^{2}\]
\[x ^{2} + y^{2} = 16 \cos^{2} t+ 16 \sin ^{2}t= 16 (\cos^{2} t+ \sin ^{2}t)=16\times1=16\]
\[i.e. x ^{2} + y^{2} = 16\]

Answer 8

thank you so much!! :)