Question

There is a rectangle where the length is double the width and the perimeter is 24 feet. Write an equation that can be used to determine the length and width of the rectangle, and use it to find the dimensions. Indicate the step where variables are defined, the equation used to solve, and the final answer.

Answer 1

helpp

Answer 2

say, length = l, width = w

Answer 3

try to form equations using the given info

Answer 4

length is double the width

\(l = 2w\) -----------------------------(1)

Answer 5

thats ur first equation

Answer 6

2w + 4l = 24??

Answer 7

close

Answer 8

perimeter is 24 feet

\(2(l+w) = 24\)

\(l+w = 12\)----------------------------(2)

Answer 9

your second equation

Answer 10

using those two equations, you need to find the length \(l\), and width \(w\)

Answer 11

so the equation is 2w + l + l = 24

Answer 12

im confused

Answer 13

both equations you need to use

Answer 14

let me show you how to solve

Answer 15

take equation (2)

\(l + w = 12\)

plugin \(l = 2w\)

Answer 16

\(2w + w = 12\)

Answer 17

so 4 is the answer

Answer 18

\(3w = 12\)

\(w = 4\)

Answer 19

width is 4, you still need to find the length \(l\)

Answer 20

for \(l\), just plugin w=4, in equation (1)

Answer 21

\(l = 2w\)
= 2(4)
= 8

Answer 22

so, the dimensions of rectangle are :
length = 8
width = 4

Answer 23

see if that makes sense. read ur question completely. it wants you to explain how we worked out... so spend some time on this ok :)