Question

Let θ be an angle in quadrant II such that sin

Answer 1

can you continue from here?

Answer 2

Thanks. I'm not sure what to do from here.

Answer 3

tan x = opposite / adjacent = -1 / sqrt15

sec x = hypotenuse / adjacent = ?

Answer 4

http://faculty.wlc.edu/buelow/PRC/T-2_1.jpg

Answer 5

Alright now I see. Thanks to both of you.

Answer 6

yw

Answer 7

Would the hypotenuse become a negative when calculating sec? Or would it just be: sec x = 4/sqrt15?

Answer 8

Or better yet, why did the 1 become negative when calculating the tangent?

Answer 9

Because your function is in the second quadrant where sine is positive and cosine is negative.

Answer 10

the whole ratio became negative
tangent :
opposite = 1 , adjacent = - sqrt15

tan = 1 / -sqrt15 = -1/sqrt15

Answer 11

\[\large \left(-\frac{1}{\sqrt{15}}\right)\]

Answer 12

So, sec = -4/sqrt15?

Answer 13

yes

Answer 14

ahh okay I see now thanks.

Answer 15

x values to the left of y-axis are negative
y values below x axis are also negative