Find the standard form of the equation of the parabola with a focus at (3, 0) and a directrix at x = -3.
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OpenStudy (anonymous):
Dan, I needed help on my last question still :(
OpenStudy (anonymous):
(6, 6)
OpenStudy (anonymous):
x+3/y^2
OpenStudy (anonymous):
9/36
OpenStudy (anonymous):
1/3
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OpenStudy (anonymous):
oh 1/4
OpenStudy (anonymous):
But tahts not one of my options dan! :( on the last Q it wasnt one of the options either
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
y = +-4x + 12
OpenStudy (anonymous):
But dannnn ... :(
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OpenStudy (anonymous):
y = (1/12)x^2
-12y = x^2
x = (1/12)y^2
y^2 = 6x
OpenStudy (anonymous):
what do i do to our equation that turns it into one of those?
OpenStudy (anonymous):
(3, -3)
OpenStudy (anonymous):
well it goes all the way to -3
OpenStudy (anonymous):
Darn it... :/ im sorry if i was confusing
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OpenStudy (dan815):
start over, look up what a directrix means, give me a picture i can work with and ill tell you the formula
OpenStudy (anonymous):
okay one sec please dont go anywhere
OpenStudy (anonymous):
A parabola is defined as follows: For a given point, called the focus, and a given line not through the focus, called the directrix, a parabola is the locus of points such that the distance to the focus equals the distance to the directrix.
@dan815