Choose the slope-intercept equation of the line that passes through the point (6, -6) and is perpendicular to y = 3x - 6.

Question

compassionate · Answer

Hello, do you know the first step?

anonymous · Answer

For two lines to be perpendicular, their slopes must be negative reciprocals of each other. So, for our new line,
$$m = \frac{ -1 }{ 3 }$$
Now, you have the slope and a point on the line, so plug that into the equation:
$$y-y_1=m(x-x_1)$$ and of course, simplify if needed.

anonymous · Answer

idk how @vinnv226

anonymous · Answer

Ok, we'll start by plugging in our values:
$$y- -6 = (-1/3)(x-6)$$$$y+6=(-1/3)(x-6)$$Now we'll distribute our slope:
$$y+6=(-x/3)+2$$Finally, subtract 6 from both sides:
$$y=(-x/3)-4$$

anonymous · Answer

Choose the equation of the vertical line that passes through the point (-5, 9). @vinnv226

anonymous · Answer

A vertical line is always of the form 
$$x=c$$where c is some constant. Since you know the coordinates of a point (-5,9) all the values on that vertical line have to have -5 as their x coordinate. So your equation is
$$x=-5$$

anonymous · Answer

Identify the correct slope and y-intercept of the equation y - 4x = -3 @vinnv226