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Mathematics 14 Online
OpenStudy (anonymous):

What is the volume of the composite figure shown? (Use 3.14 for π.) figure shown in comments

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

this composite figure is made up of a cylinder and a cone so you'll use the formulas Volume of a Cylinder: V = pi*r^2*h Volume of a Cone V = (1/3)*pi*r^2*h

jimthompson5910 (jim_thompson5910):

r = radius h = height

OpenStudy (anonymous):

so that is 7x7= 49

jimthompson5910 (jim_thompson5910):

the radius will be the same for both, but the heights are different for the two figures

jimthompson5910 (jim_thompson5910):

in the case of the cylinder, r = 7 h = 6 for the cone, r = 7 h = 7

jimthompson5910 (jim_thompson5910):

yes you'll have 7^2 = 7*7 = 49 in there somewhere

OpenStudy (anonymous):

so for the cone it's 49 and the cylinder is 42

jimthompson5910 (jim_thompson5910):

not quite

OpenStudy (anonymous):

in confused

jimthompson5910 (jim_thompson5910):

Volume of the Cylinder: V = pi*r^2*h V = pi*7^2*6 V = pi*49*6 V = pi*294 V = 294pi Volume of the Cone V = (1/3)*pi*r^2*h V = (1/3)*pi*7^2*7 V = (1/3)*pi*49*7 V = (1/3)*pi*343 V = (1/3)*343*pi V = (343/3)*pi These two volumes add to get the volume of the composite figure Volume of Composite Figure = Volume of Cylinder + Volume of Cone Volume of Composite Figure = 294pi + (343/3)*pi Volume of Composite Figure = ( 294 + 343/3)*pi Volume of Composite Figure = ( 294*3/3 + 343/3)*pi Volume of Composite Figure = ( 882/3 + 343/3)*pi Volume of Composite Figure = ( (882 + 343)/3)*pi Volume of Composite Figure = (1225/3)*pi

jimthompson5910 (jim_thompson5910):

since we're using 3.14 for pi, this means Volume of Composite Figure = (1225/3)*pi Volume of Composite Figure = (1225/3)*3.14 Volume of Composite Figure = 1,282.16666666667 and you can round that however you need to

OpenStudy (anonymous):

so it would be 1.282.17?

jimthompson5910 (jim_thompson5910):

if you're rounding to 2 decimal places, yes

OpenStudy (anonymous):

Ok, thanks so much!!

jimthompson5910 (jim_thompson5910):

you're welcome

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