please help
Use the Substitution Method to solve the following system of equations.
2x + y = 3
-3x + 4y = 1
(1, 1)
(-1, -1)
(1, -1)
(-1, 1)
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jimthompson5910 (jim_thompson5910):
solve the first equation for y
2x + y = 3
y = 3 - 2x
then plug this into the second equation
-3x + 4y = 1
-3x + 4(3 - 2x) = 1 .. replace y with 3-2x
-3x + 12 - 8x = 1
solve for x, then use this to solve for y
OpenStudy (anonymous):
so x=1?
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
now plug that back into y = 3 - 2x to find y
OpenStudy (anonymous):
y=3+2x?
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jimthompson5910 (jim_thompson5910):
y = 3 - 2x
jimthompson5910 (jim_thompson5910):
it's minus, not plus
OpenStudy (anonymous):
so the answer is? (1,1)
jimthompson5910 (jim_thompson5910):
perfect
OpenStudy (anonymous):
thank you!
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jimthompson5910 (jim_thompson5910):
you're welcome
OpenStudy (anonymous):
what about this one?
What is the value of the x variable in the solution to the following system of equations?
2x + 3y = 4
x - 2y = -5
2
-2
1
-1
jimthompson5910 (jim_thompson5910):
first solve for x in x - 2y = -5 to get
x - 2y = -5
x = -5+2y
now plug this into the first equation
2x + 3y = 4
2(-5+2y) + 3y = 4
-10+4y + 3y = 4
solve for y, then use this to solve for x
OpenStudy (anonymous):
y=2
jimthompson5910 (jim_thompson5910):
good, then use that to find x
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OpenStudy (anonymous):
how do I do that?
jimthompson5910 (jim_thompson5910):
well remember we isolated x and got x = -5+2y
jimthompson5910 (jim_thompson5910):
so if y = 2, then
x = -5+2y
x = -5+2*2 ... replace y with 2 (since y = 2)
x = -5 + 4
x = -1
OpenStudy (anonymous):
thank you :)
jimthompson5910 (jim_thompson5910):
you're welcome, keep practicing this and you'll definitely be a pro in no time
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