Find the domain of the radical function.
PLEASE HELP if you can show steps please
you dont know anything just asking help
the domain of the function will be in other words "what values can 'x' take and YET not make the square root NEGATIVE?" so, what value for "x" will yield a negative number inside the root you think?
x < with a line under 7?
let's try say 5 x = 5 \(\color{blue}{\sqrt{7-(5} \implies \sqrt{2}}\) so, that didn't make it negative, thus "x" can take that value, so 5 is part of the domain
so, what will make the inside of the root, negative?
did i get the correct answer?
what makes you think is \(x \le 7 \large \ ?\)
i looked it up on how to solve it n i got that
yes, why is it right though? how do you even know is right?
im guessing you would plug it back in?
when they ask for the domain on an expression with a root, usually is meant, what would NOT make the root negative
so inside the root you have 7-x so, what values for "x" will KEEP the expression POSITIVE? is pretty much what's being asked
so, let's try a few "x" say try x = 2, 3, 4, 7, 9, 11 try those
you want me to plug those numbers in?
yeah
11 and 9 wouldnt work
to see which of those numbers for "x", will make keep the expression POSITIVE
11 and 9 wouldn't? why not?
cuz they give you a negative number
ohhh how about 7?
gives you 0
how would you do that then
so, if x is 2, 3, 4 ,5, 6 you get some POSITIVE value if x is 7, you get 0 after 7, the expression goes into negative so the values "x" can take while keeping the expression POSITIVE are the values of 7 OR LESS so "x can be equals to 7 or less than 7" that is \(\huge\color{blue}{ x \le 7}\)
thanx that really helps
that one is done the same exact way plug values for "x", if it becomes 0 or more is fine once it "below" 0, or negative, then that's where the domain stops
its multiple choice
if you notice 2*3 = 6, so 6-2(3) = 6-6 =0 so x can be 3 or LESS
Join our real-time social learning platform and learn together with your friends!