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Mathematics 20 Online
OpenStudy (anonymous):

Find the domain of the radical function.

OpenStudy (anonymous):

OpenStudy (anonymous):

PLEASE HELP if you can show steps please

OpenStudy (anonymous):

you dont know anything just asking help

OpenStudy (jdoe0001):

the domain of the function will be in other words "what values can 'x' take and YET not make the square root NEGATIVE?" so, what value for "x" will yield a negative number inside the root you think?

OpenStudy (anonymous):

x < with a line under 7?

OpenStudy (jdoe0001):

let's try say 5 x = 5 \(\color{blue}{\sqrt{7-(5} \implies \sqrt{2}}\) so, that didn't make it negative, thus "x" can take that value, so 5 is part of the domain

OpenStudy (jdoe0001):

so, what will make the inside of the root, negative?

OpenStudy (anonymous):

did i get the correct answer?

OpenStudy (jdoe0001):

what makes you think is \(x \le 7 \large \ ?\)

OpenStudy (anonymous):

i looked it up on how to solve it n i got that

OpenStudy (jdoe0001):

yes, why is it right though? how do you even know is right?

OpenStudy (anonymous):

im guessing you would plug it back in?

OpenStudy (jdoe0001):

when they ask for the domain on an expression with a root, usually is meant, what would NOT make the root negative

OpenStudy (jdoe0001):

so inside the root you have 7-x so, what values for "x" will KEEP the expression POSITIVE? is pretty much what's being asked

OpenStudy (jdoe0001):

so, let's try a few "x" say try x = 2, 3, 4, 7, 9, 11 try those

OpenStudy (anonymous):

you want me to plug those numbers in?

OpenStudy (jdoe0001):

yeah

OpenStudy (anonymous):

11 and 9 wouldnt work

OpenStudy (jdoe0001):

to see which of those numbers for "x", will make keep the expression POSITIVE

OpenStudy (jdoe0001):

11 and 9 wouldn't? why not?

OpenStudy (anonymous):

cuz they give you a negative number

OpenStudy (jdoe0001):

ohhh how about 7?

OpenStudy (anonymous):

gives you 0

OpenStudy (anonymous):

OpenStudy (anonymous):

how would you do that then

OpenStudy (jdoe0001):

so, if x is 2, 3, 4 ,5, 6 you get some POSITIVE value if x is 7, you get 0 after 7, the expression goes into negative so the values "x" can take while keeping the expression POSITIVE are the values of 7 OR LESS so "x can be equals to 7 or less than 7" that is \(\huge\color{blue}{ x \le 7}\)

OpenStudy (anonymous):

thanx that really helps

OpenStudy (jdoe0001):

that one is done the same exact way plug values for "x", if it becomes 0 or more is fine once it "below" 0, or negative, then that's where the domain stops

OpenStudy (anonymous):

its multiple choice

OpenStudy (jdoe0001):

if you notice 2*3 = 6, so 6-2(3) = 6-6 =0 so x can be 3 or LESS

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