What mass of sodium chloride is produced if 92.0 g if sodium reacts with excess chlorine?
\(\Huge\bf \color{black}{Welcome~to~OpenStudy!!}\hspace{-310pt}\color{black}{Welcome~to~OpenStudy!!}\hspace{-307.1pt}\color{#ff7100}{Welcome~to~\color{#00B4ff}{Open}}\color{#7cc517}{Study!!}\) First step: write the reaction equation
2Na + Cl2 --> 2NaCl
Oke so the ratio is 2:1:1 when 2 moles of sodium reacts with 1 mole of chlorine, 2 moles of sodiumchloride is produced Take a look at the diagram i attached to this post, Calculate how many moles are in 92.0 gram sodium
i am so confused. this is like speaking a different language to me
We have the mass of the Na in gram. We need the amount of moles Na. So you divide by the molecular mass of Na. You can find the molecular mass in a periodic table Like here: http://www.ptable.com
so is the molecular mass 22.99?
yes, so when you have 92 gram Na and the mol. mass is 22.99, How many moles Na do you have? (remember, divide by molecular mass)
4.0?
Yes, so we have 4 moles sodium. We know that 2 moles of sodium reacts with 1 mole chlorine to produce 2 moles sodiumchloride. We now calculate the amount of moles of sodiumchloride that is produced with 4 moles sodium. The ratio is 2:2
my question is multiple choice.. the options are a) 234 g NaCl b) 63 g NaCl c) 116 g NaCl d) 58.5 g NaCl
Yea but we don't need multiple choice, we can calculate it :) So how many moles NaCl is produced with 4 moles Na?
how do i calculate it?
Well with the ratio :) we know 2 mol Na --> 2 mol NaCl So for 4 mol Na, how many mol NaCl?
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