Perform the requested operation or operations. f(x) =x-3/5 ; g(x) = 5x + 3, find g(f(x)).
all this means is instead of x in g(x) you need to replace it with x - 3/5 so you are looking at \[g(\frac{x - 3}{5}) = 5(\frac{x -3}{5}) + 3\] just distribute and collect liek terms in g(x) hope this helps
$$ f(x) =\color{red}{\frac{x-3}{5}}\\ g(x) = 5x + 3\\ g(f(x)) = 5\pmatrix{\color{red}{\frac{x-3}{5}}} + 3 $$
=3/5
f(g(x))=x-3/5
not quite distribute and you get \[g(\frac{x -3}{5}) = 5 \times \frac{1}{5} (x - 3) + 3\] so you have \[g(\frac{x -3}{5}) = x - 3 + 3\] just finish it off
f(g(x))=x+6
nope just be careful with the signs -3 + 3 = 0 so what are you left with..?
$$ f(x) =\frac{x-3}{5}\\ g(x) = \color{red}{5x + 3}\\ f(g(x)) = \frac{(\color{red}{5x + 3})-3}{5} $$
Oh, poop...Thank you so much! I always forget the signs
glad to help
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