Find f(x) and g(x) so that the function can be described as y = f(g(x)). y = 3/sqrt3x+4
\[y=\frac{ 3 }{ \sqrt{3x+4} }\]
@jim_thompson5910 can you help? Please:)
are you given answer choices?
because this question is open-ended (ie there are multiple ways to do this)
off the multiple choices as jim_thompson5910 already pointed out think about if you were to make f(x) = 3/x what will be your g(x)?
f(x) = \[\frac{ 3 }{ \sqrt{x} }\], g(x) = 3x + 4 f(x) =\[\sqrt{3x+4}\] , g(x) = 3 f(x) =\[\frac{ 3 }{ x }\] , g(x) = 3x + 4 f(x) = 3, g(x) = \[\sqrt{3x+4}\]
Sorry thats really hard to read but those are the answer choices
A) f(x) =3/sqrt x , g(x) = 3x + 4 B) f(x) = sqrt 3x+4 , g(x) = 3 C) f(x) = 3/x , g(x) = 3x + 4 D) f(x) = 3, g(x) = sqrt 3x+4
Answer choices!
if you look at choice C, saying f(g(x)) would get you this f(x) = 3/x f(g(x)) = 3/(g(x)) ... replace every x with g(x) f(g(x)) = 3/(3x+4) ... replace every g(x) on the right with 3x+4 so this is close to what we want, but not quite
so C is out
Okay!
see how I got that?
Yes
so what is f(g(x)) for choice B?
\[\sqrt{13}\]
so that's out too because that's not what we want
for choice D, f(x) is always 3, so no matter what you plug in for x, it's going to remain 3 besides, there is no x to replace anyway (on the right side) so for choice D, f(g(x)) = 3 so D is out
Okay, so the answer is a
yep, I would do the same thing we've been doing to check though (so you get the practice)
okay, Thank you so much!
yw
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