Question

State the horizontal asymptote of the rational function.
f(x)=9x^2-3x-8/4x^2-5x+3

Answer 1

what is the degree of the numerator?

Answer 2

numerator: 9x^2-3x-8....so it would be squared

Answer 3

the degree of the numerator is 2
also the degree of the denominator is 2

since the degrees are the same, the horizontal asymptote is the ratio of the leading coefficients

Answer 4

so it would be x=1?

Answer 5

which in your case it \(\frac{9}{4}\) so it is
\[y=\frac{9}{4}\]

Answer 6

9/4?

Answer 7

yes

Answer 8

thank you

Answer 9

horizontal asymptote is a horizontal line, so it should look like
\[y=something\]not \[x=something\]

Answer 10

yw