Give an example of a rational function that has a horizontal asymptote at y = 1 and a vertical asymptote at x = 4.
what a great question what must the denominator look like if the vertical asymptote is \(x=4\) ?
(x-4)?
exactly
and horizonal 1/x?
well, it could also be \(2x-8\) but why not keep it simple and write what you did
so you know it looks like \[\frac{something}{x-4}\] all you need is the "something"
the horizontal asymptote is \(y=1\) and the degree of the denominator is \(1\) so what must the degree of the numerator be?
x-1?
that would work, yes, but maybe not for the reason you think
the degree of the numerator must be the same as the degree of the denominator, and the degree of the denominator is 1, so it could be \[\frac{x}{x-4}\]
or it could be \[\frac{x-1}{x-4}\]if you like
and that would answer both questions?
either way the degree of the numerator must be 1, and the leading coefficient must also be 1 so you can use any example you like, so long as the denominator is \(x-4\) and the numerator starts with \(x\)
your example would work fine so would \[\frac{x+5}{x-4}\] anything reallyl
alright thanks again!
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