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Find the derivative of log2(x^2/2)
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\[\log_2(x^2/2)\]
My answer was \[1/(x^2/2)\ln2\] I don't believe it needs to be in simplest form
\[\log_{2} (x^2/2)= \log_{2}x^2-\log_{2}2=2\log_{2}x-1 \]
take derivative, (1)' =0 therefore just the first term needs to calculate
\[\frac{2}{xln2}\]
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The final answer is \[2/xln2\]
I think so.
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