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Need help!!! please!! The present value of the building in the downtown area is given by the function : P(t) = 300,000e^-0.09t+square root of t, over 2. For t = and grater than 0 and t = and less than 10. Find the optimal present value of the building. ( Hint : the slope of the tangent line is 0.)
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I am very confusing
e^-0.09(o)+square root of 0 over 2 = e^0 = 1 right ?????
P(0)= 300,000 (1) = 300,000 dollars ???
I hope somebody can help me tomorrow!!
Derive the present Value function to get P'(t). Make the derivative = zero and solve for t. Take the solution within the interval o<t<10. Just substitute the value of that t back into Present value function. I think that's what you do.
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Thank you mebs !!!!
yw
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