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Solve. 8 = 2^(x + 4)
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8 = 2^x + 4 2^x = 4 2^x = 2^2 x = 2
Here are the answer choices: x = -1 x = -4 x = 0 x = 7
it =0 my friend
2(x+4)=8 x+4 = 8/2 = 4 x=4-4 = 0
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itz -1 8 =\[2^{x+4}\] =>\[2^{3}\]=\[2^{x+4}\] therefore 3=x+4 =>x=-1
@alex8ac for 8 = 2^(x + 4) not havin a go at u man, just helpin u out with the symbols we use here the ^ usually means "to the power of" so 8 = 2^(x + 4) in this case means \[8 = 2^{(x + 4) }\] so as @Rex831 said before, you'd either use known powers or logarithms to work this one out \[\log_{2} 8 = \log_{2} 2^{(x+4)}\] so 3 = x +4 so x = -1
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