Question

I have a calculus question in which im not sure how to solve. The question asks to use a triple integral to find the volume of the solid bounded by the graph of the equation x^2+y^2+z^2=9

Answer 1

well, you have a sphere centered at the origin of radius 3 to start with

Answer 2

is this a dxdydz, or a spherical triple?

Answer 3

i have thats i also set the equation to z and got the bounds x=0 to 3, y=0 to sqrt(9-x^2) z=0 to sqrt(9-x^2-y^2) its a dzdydx

Answer 4

im not sure if my bounds are correct though, this is my first attempt at it

Answer 5

bravo :D

Answer 6

That just takes one eighth of its volume, however, as you have set the bounds to only be in the first octant.

Answer 7

x^2+y^2+z^2=9 solving for z get us:

+- sqrt(9-x^2-y^2), starting at 0 is only giving you half the results ... but thats fine if you want to go there

Answer 8

ill just multiply the other parts in after i have solved the volume for a section of it

Answer 9

not sure where to go from there though

Answer 10

Multiply? add?
Once you've solved the volume for the first octant, take advantage of the fact that the sphere is symmetrical... and just multiply the result by 8 :)

Answer 11

yup but the problem is im not sure how to solve the first onctant, are my bounds correct, its the part im having trouble with