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Find the missing term in factoring perfect squares of a trinomial- ?-xy+y^2
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(a - b)^2 = a^2 - 2ab + b^2 For the last term the trinomial has y^2; that means the second term of the squared binomial must be y. ( - y)^2 Notice that when you have (a - b)^2, the middle term is -2ab. Here you only have -xy. If the first term of the binomial were x, then (x - y)^2 would give a middle term of -2xy, but you only have -xy, so the first term of the binomial must be x/2. Now we have the binomial squared as: ( x/2 - y)^2 If you square it, you get: (x^2)/4 - xy + y^2
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