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Solve the equation y′ + 3y = t + e^(−2t).
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solve it for y ?
...the first term is y squared ?
its a diffyQ
solve the =0 part, then there are a few methods for the second part of it assume At + Be^(-2x) is a particular solution and give it a runthru; if not, then modify as needed
3y = 3At + 3Be^(−2t) y' = A - 2Be^(−2t) -------------------- it looks like B=1 would be good for that part of it, but we would need to modify the At.
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