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Physics 6 Online
OpenStudy (anonymous):

A skateboarder with a mass of 45 kilograms is riding on a skateboard with a mass of 2.5 kilograms. What should be the velocity of the skateboarder if she has to attain a momentum of 264 kilogram meters/second? Blaaah Physics.-.

OpenStudy (anonymous):

Would this also be P=m8v?

OpenStudy (anonymous):

p=m*v sorry

OpenStudy (anonymous):

You know the mass of skateboarder=45 and the momentum to be attained =264 p=mv

OpenStudy (anonymous):

It is asking momentum of skateboarder only and not skateboarder+skateboard. So m is mass of skateboarder only.

OpenStudy (anonymous):

so it will be 264=45*v? I divide the 264 by 45 which i get 5.8?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

The closest option i have is 5.5 meters/second.

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