Question

Solve the integration : ∫cotx log(sinx) dx

Answer 1

substitute sinx = t
see if this helps

Answer 2

I did.

Answer 3

Do you want me to show what did I do ?

Answer 4

just tell me where you are stuck ?

Answer 5

i ain't stuck anywhere.. it's just i'm not getting the answer i'm supposed to get.

Answer 6

Okay, So I took sinx = t
=> ∫ cosx/sinx log(sinx) dx
= ∫ (log t)/t dt
let 1/t = p
=> dp = log(t).dt
=> ∫log t / t .dt = ∫1/p dp
= log p = log (1/t) = log (1/sinx) ..

Where am i wrong ?

Answer 7

the third step
if you let 1/t = p
then dp = -dt/t^2

anyways dont make that substitution,
go for logt = p

Answer 8

Thanks.
We are anyways supposed substitute log(sinx) as t in the first step.
Maybe because of the same reason ;)

Answer 9

P.s : @shubhamsrg - Can't naughty girls be nerdy ??

Lol. Jk. Fake Picture.

Answer 10

yeah.. log(sinx) = t was enough .

Answer 11

hmm
I was coming to it
https://twitter.com/sexytoyin
http://www.facebook.com/sonal.thomas.39

dafaq is it with fake profiles? :/

Answer 12

Who said anything about a fake profile ?
I just have a fake picture, I am 100% real though ;)

Answer 13

sure.. -_-

Answer 14

nevermind, doesn;t matter to me, as long as you stick to mathematics in this section sie! ^^

Answer 15

sir*

Answer 16

you preparing for jee next year or something?
its not a bad idea to use a girl's profile, girls get more responses here .-.

Answer 17

Hold on mister :P
I still am a miss :P
It's just a fake picture :P

And, No.
I won't be able to crack it anyways

Answer 18

@shubhamsrg : Which std are you in?

Answer 19

I gave my jee main and adv this year, could not clear adv.
you cant possible convince me! :D
do not worry, am not gonna back bite/spread the news