Question

can you help walk me through this problem and show me how to do this?

Answer 1

\[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\]

Answer 2

first write all in terms of \(\sqrt{2x}\)

Answer 3

\(3\sqrt{2x}\) is already in terms of \(\sqrt{2x}\) so lets leave it alone for the moment

Answer 4

\(\sqrt{8x}=\sqrt{4\times 2x}=\sqrt{4}\sqrt{2x}=2\sqrt{2x}\) so now we have
\[x\sqrt{8x}=2x\sqrt{2x}\]

Answer 5

and finally \[-5\sqrt{18x}=-5\sqrt{9\times 2x}=-5\times \sqrt{9}\sqrt{2x}=-15\sqrt{2x}\]

Answer 6

so now everything is written in terms of \(\sqrt{2x}\)

Answer 7

\[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\]
\[=3\sqrt{2x}+2x \sqrt{2x}-15\sqrt{2x}\]

Answer 8

now i guess you can combine like terms
you are sure the middle one was \(x\sqrt{8x}\) right?

Answer 9

yep

Answer 10

okay then the best you can do it
\[2x\sqrt{2x}-12\sqrt{2x}\] unless you want to factor out the \(\sqrt{2x}\) and write
\[(2x-12)\sqrt{12}\]

Answer 11

you are a life saver! :) thank you

Answer 12

yw
hope the steps were more or less clear