Question

Write the equation of a hyperbola with a center at (-5, -3), vertices at (-5, -5) and (-5, -1) and co-vertices at (-11, -3) and (1, -3).

Answer 1

id move it to the origin, and then adjust it back to center

Answer 2

Write the equation of a hyperbola with a

center at (-5+5, -3+3),
vertices at (-5+5, -5+3) and (-5+5, -1+3)
co-vertices at (-11+5, -3+3) and (1+5, -3+3).

Answer 3

it is a vertical hyperbola, because the vertices are above and below the center.
Equation will be:
\(\frac{(y-c_1)^2}{a^2} - \frac{(x-c_1)^2}{b^2} = 1\).
The center of the parabola is \((c_1,c_2)\).
\(a\)=distance between center and vertex.
\(b\)=distance between center and covertex.
Replace in the formula.

Answer 4

hyperbola*

Answer 5

Thanks!

Answer 6

i mean \((y-c_2)^2\) *

Answer 7

write here what you find?

Answer 8

Would it be (y +5)^2 / 4
for the first part?

Answer 9

almost, it's (y+3)^2 /4, you must the y-coordinate in the (y-..)^2 parenthesis.

Answer 10

it is then clear that it will be (x+5)^2/36 for the other part.

Answer 11

Okay, thanks (:

Answer 12

yw