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(1-sin(pi/8))(1+sin(pi/8))
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1-sin^2(pi/8)
1+sin(pi/8)-sin(pi/8)-sin^2(pi/8)
=cos^2(pi/8)
And that is equal? How to find out :) ?
\[\cos^2x+\sin^2x = 1\]\[1-\sin^2x = \cos^2x\]
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You want to evaluate \(\cos^2(\pi/8)\)?
yes :)
How to find out what cos2(π/8) is
cos^2(pi/8)
Okay, that's easy enough. Use the identity \[\cos^2 u = \frac{1+\cos 2u}{2}\]
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\(u = \pi/8\) so \(2u = \pi/4\) and you can find the \(\cos\) of that easily.
cos^2x=(1+sqr2/2)/2
?
=(2+sqr2)/4
That's correct. About 0.853553 if evaluated.
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Tyvm :)
yw :)
study those identity lists!
Will do :D
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