1. A game is said to pay “3 to 1” if for every $1 bet you win, you get paid $3. In roulette, there are 40 spaces on the wheel: 19 red, 19 black, and 2 green. Red and black pay 2 to 1 and green pays 20 to 1.
what is the probability that I land on black at least once in 3 spins?
This is how I thought to do it. Let me know if I did it right.
p(at least one black = 1-(21/40)^3
p(at least one black = 1-(0.525)^3
p(at least one black = 1-0.145
p(at least one black = 0.855*100%=85.5%

Question

1.	A game is said to pay “3 to 1” if for every $1 bet you win, you get paid $3.  In roulette, there are 40 spaces on the wheel: 19 red, 19 black, and 2 green.  Red and black pay 2 to 1 and green pays 20 to 1.  
what is the probability that I land on black at least once in 3 spins?
This is how I thought to do it. Let me know if I did it right.
p(at least one black = 1-(21/40)^3
p(at least one black = 1-(0.525)^3
p(at least one black = 1-0.145
p(at least one black = 0.855*100%=85.5%

jim_thompson5910 · Answer

you are correct

you calculate the probability of not landing on black in 3 spins and that's (21/40)^3

you then find the complement of that event to get your answer

anonymous · Answer

thank you I thought I was on the right path

jim_thompson5910 · Answer

you're welcome