Question

Is there any way to integrate the following function and get a decent looking answer?
\( \int se^{-s^2} ds\)

Answer 1

We'll need a u substitution. Set u=-s^2:
\[u=-s^{2}\]
\[du=-2s \times ds\] Now we'll plug this in, putting a -1/2 in front:
\[(-1/2)\int\limits_{}^{} e^{u} du\] The integral of e^u is e^u so:
\[(-1/2)e^{u}\] which is
\[(-1/2)e^{-s^{2}}\]

Answer 2

Ohh yaaaa I forgot I can use substitution. -_-

Answer 3

Thanks :)

Answer 4

No problem, glad I could help.

Answer 5

Don't forget the +C on the end though, if you're not plugging in values.

Answer 6

Yaaaaaa thats vital. Thanks for reminding me