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Physics 22 Online
OpenStudy (anonymous):

A stone of mass 0.55 kilograms is released and falls to the ground. Measurements show that the stone has a kinetic energy of 9.8 joules at the point of impact with the ground. What is the stone's velocity when it hits the ground?

OpenStudy (shane_b):

\[KE=\frac{1}{2}mv^2\]\[9.8J=\frac{1}{2}(0.55kg)v^2\]Solve for v.

OpenStudy (anonymous):

thx :)

OpenStudy (shane_b):

np :)

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