I anyone up to helping me to solve a quadratic multiplication with no negative exponents in the answer, if so please help. (a^-2 c^1/5)^2/3
start with \[a^{-2\times \frac{2}{3}}c^{\frac{1}{5}\times \frac{2}{3}}\]
I have and got a^2/3 c 2/15 am I close?
not quite
\[-2\times \frac{2}{3}=-\frac{4}{3}\]
\[\large a^{-\frac{4}{3}}c^{\frac{2}{15}}\]
Ok, so my answer is a^43/c^2/15
Since the answer cannot have negative exponents I have to write it as a fraction correct?
so I think the answer is a^4/3/c^2/15
oh no!
writing with positive exponents does not mean to change the minus sign to a plus sign it means to put it in the denominator!
\[\large \frac{c^{\frac{2}{15}}}{a^{\frac{4}{3}}}\]
Ok, I think I understand now. I am being asked to write the answer in simplest form how do I do that? The writing is so small is that c^1/15 or c^2/15 over a ^4/2 ir ^4/3
Never mind, I think I have it thank you!
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