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OpenStudy (anonymous):
3HBr + Al(OH)3 ----> 3H2O + AlBr3 If 8.56 grams of HBr react with an excess of Al(OH)3 to form 8.91 grams of AlBr3, what is this reaction’s percent yield? Haven't done this in 4ever can someone please do it and show me in the simplest steps possible? I will be extremely grateful
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