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Mathematics 7 Online
OpenStudy (anonymous):

Graph the function, with the focus and directrix shown on the graph, as well. Attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

@julian25

OpenStudy (anonymous):

OpenStudy (anonymous):

(x-2)^2 =4*1y

OpenStudy (anonymous):

the focus is 0,4?

OpenStudy (anonymous):

close the problem here is that parabola is translate to the right 2 units because the factor (x-2)

OpenStudy (anonymous):

so the focus is 0,2

OpenStudy (anonymous):

no well if the equation where x^2 = 4*1y the focus woulb be (0,4) like u say

OpenStudy (anonymous):

|dw:1372753633900:dw|

OpenStudy (anonymous):

wait the focus is in y=1

OpenStudy (anonymous):

and the directirx would be -1

OpenStudy (anonymous):

where do u got the 4

OpenStudy (anonymous):

u say (0,4) but it is (0,1)

OpenStudy (anonymous):

i got confused with the other way the one that you gave an example of

OpenStudy (anonymous):

x^2 = 4*1y

OpenStudy (anonymous):

for this equation x^2 = 4*1 the focus is (0,1)

OpenStudy (anonymous):

x^2 = 4*1y

OpenStudy (anonymous):

ok and the directrix is -1 then, right?

OpenStudy (anonymous):

and te graph is the one that i made

OpenStudy (anonymous):

yes but we are working with this (x-2)^2 =4*1y

OpenStudy (anonymous):

so u must translate the focus to the right

OpenStudy (anonymous):

ok i get it

OpenStudy (anonymous):

really? so what is the focus?

OpenStudy (anonymous):

0,1

OpenStudy (anonymous):

x^2 = 4*1y for this is (0,1)

OpenStudy (anonymous):

because you move to 2 to the right

OpenStudy (anonymous):

for that one (x-2)^2 =4*1y u must move the graph 2 units to the right

OpenStudy (anonymous):

right!

OpenStudy (anonymous):

for the directrix would the line be vertical or horizontal?

OpenStudy (anonymous):

|dw:1372754153370:dw|

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