Mathematics
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OpenStudy (anonymous):
Graph the function, with the focus and directrix shown on the graph, as well. Attachment
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OpenStudy (anonymous):
OpenStudy (anonymous):
@julian25
OpenStudy (anonymous):
OpenStudy (anonymous):
(x-2)^2 =4*1y
OpenStudy (anonymous):
the focus is 0,4?
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OpenStudy (anonymous):
close the problem here is that parabola is translate to the right 2 units because the factor (x-2)
OpenStudy (anonymous):
so the focus is 0,2
OpenStudy (anonymous):
no well if the equation where
x^2 = 4*1y the focus woulb be (0,4) like u say
OpenStudy (anonymous):
|dw:1372753633900:dw|
OpenStudy (anonymous):
wait the focus is in y=1
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OpenStudy (anonymous):
and the directirx would be -1
OpenStudy (anonymous):
where do u got the 4
OpenStudy (anonymous):
u say (0,4) but it is (0,1)
OpenStudy (anonymous):
i got confused with the other way the one that you gave an example of
OpenStudy (anonymous):
x^2 = 4*1y
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OpenStudy (anonymous):
for this equation
x^2 = 4*1
the focus is (0,1)
OpenStudy (anonymous):
x^2 = 4*1y
OpenStudy (anonymous):
ok and the directrix is -1 then, right?
OpenStudy (anonymous):
and te graph is the one that i made
OpenStudy (anonymous):
yes but we are working with this
(x-2)^2 =4*1y
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OpenStudy (anonymous):
so u must translate the focus to the right
OpenStudy (anonymous):
ok i get it
OpenStudy (anonymous):
really? so what is the focus?
OpenStudy (anonymous):
0,1
OpenStudy (anonymous):
x^2 = 4*1y for this is (0,1)
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OpenStudy (anonymous):
because you move to 2 to the right
OpenStudy (anonymous):
for that one (x-2)^2 =4*1y u must move the graph 2 units to the right
OpenStudy (anonymous):
right!
OpenStudy (anonymous):
for the directrix would the line be vertical or horizontal?
OpenStudy (anonymous):
|dw:1372754153370:dw|