In photo disintegration , a deuteron absorbs gamma -rays and split into a proton and neutron .the deuteron binding energy is 2.223Mev .what maximum energy .. must ,the proton have ?
given.(mass of deutron =2.014102 a.m.u mass of proton =1.00758 a.m.u and mass of neutron =1.00898 a.m.u )
@Preetha @thomaster @Melxo52 @Ashleyisakitty @GoldPhenoix @Luigi0210 @chmvijay @cwrw238
@vikrantg4
I have never studies Nuclear Physics. sorry ! :)
studied*
r u looking for binding energy or light energy?
maximum energyy.... released .... i hope....
i havent done maximum energy yet
i have only did binding & light energies so far
sorryy:(
its kk .....this chem is totally making me mad ......
by the way i did this in physics not chem
reallyyy ... ye mere chem ke paper mai hai yarr ....
really? i had my exam on nuclear phys and others last wk
almost done with nuclear phys for this yr
i have just started @@ ;-((
lol..gd luck
i loved it though
@chmvijay , @thomaster can u guys give it a go?
Sorry I don't know nuclear physics :(
its ok
Maybe @Frostbite
is he online?
no he is not:(
well guys i got a ans which is not at all equal to the ans given in text
i just need to know wht is the way to solve this q'
one sec ...
in text .. mass defect delta m =mass of the reactant -mass of the product(proton *newtron and ans is 0.002728 a m u i am not getting this ans
I just write some things I got in my mind. No idea if it may work: Principal of energy conservation: \[E _{before}=E_{after}\] The contributions to E_before most be: the mass defect and the energy entering the system as photons: \[E_{before}=E _{photon}+m_{defect}*c ^{2}\] We assume that Eafter is only the binding energy and ignore any kinetic energy or light emission: \[E _{after}=E _{bond}\] It most then follow from our generalizations: \[E _{photon}+m_{defect}*c ^{2}=E _{bond}\]
thnaks ... i will compare and try it
Try check your answer with: \[E _{photon}=hf\] It should be in the gamma area else we can discard the solution.
kk
\[m_{defect}=Z*m_{proton}+N*m _{neutron}-m _{core}\]
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