Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

diffrenciate with respect to x sec(tanx)

OpenStudy (anonymous):

sec(tan x).tan(tanx).sec^2x

OpenStudy (anonymous):

can u give the method??? solve full question please!

terenzreignz (terenzreignz):

Chain rule... and the 'hit list'. First, identify the outermost function, the function that sorta 'contains' all the others... which is it?

OpenStudy (anonymous):

cn u solve full question fr me

terenzreignz (terenzreignz):

Of course I can...but then again... YOU have to do it... I'm just here to help you along... :)

OpenStudy (anonymous):

pls hlp me!!! give me the full method and solution

terenzreignz (terenzreignz):

Yes, I'm here to help you... but not do it for you. There's a difference :) Now, please help me... help you. What's the outermost function of sec(tan(x)) ?

OpenStudy (anonymous):

sorry, i didnt get ur question

terenzreignz (terenzreignz):

Outermost... the one that contains all the others...

OpenStudy (anonymous):

secx=secx*tanx

terenzreignz (terenzreignz):

Let me just fix that... \[\Large \sec(x) \color{red}\neq \sec(x)\tan(x)\]\[\Large \frac{d}{dx}\sec(x) = \sec(x)\tan(x)\]

terenzreignz (terenzreignz):

Okay, good, so you know that the derivative of sec(x) is sec(x)tan(x) So, part of the derivative of sec(tan(x)) would be sec(tan(x))tan(tan(x)) okay?

OpenStudy (anonymous):

kkk

terenzreignz (terenzreignz):

Now, once you've gotten rid of the sec(x) what's the next function (the one that's immediately inside the sec() )?

OpenStudy (anonymous):

i got it

terenzreignz (terenzreignz):

You're sure? Okay then.

OpenStudy (anonymous):

tanx=sec^2x

terenzreignz (terenzreignz):

So you multiply this to the sec(tanx)tan(tanx)

OpenStudy (anonymous):

can i send u frnd request

terenzreignz (terenzreignz):

All in good time.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!