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solve tan (x+75')=2.4562 , 0'≤x≤360'
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Ok, to remove a tangent from one side of an equation, you need to take it by inverse tan. As well you need to do it to the otherside also. \[x+75=\tan^{-1} (2.4562)\] Then you would subtract the 75 over. \[x=\tan^{-1}(2.4562) - 75\]
the reflex angle is 67.847' it is placed in first and third quadrant x+75= 67.85, 247.85 x=-7.15, 172.85? but the answer cant be -value
I got -75.8176, and you can indeed get a negative degree. It just means that it went around the unit circle in the opposite direction.
but the answer is 172.8 and 352.8
Apologies, I got -73.8158.
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I'm not sure then. Sorry I couldn't be of more help.
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