solve tan (x+75')=2.4562 , 0'≤x≤360'

Question

solve tan (x+75')=2.4562   , 0'≤x≤360'

austinl · Answer

Ok, to remove a tangent from one side of an equation, you need to take it by inverse tan. As well you need to do it to the otherside also.
$$x+75=\tan^{-1} (2.4562)$$
Then you would subtract the 75 over.
$$x=\tan^{-1}(2.4562) - 75$$

anonymous · Answer

the reflex angle is 67.847'
it is placed in first and third quadrant
x+75= 67.85, 247.85
x=-7.15, 172.85?
but the answer cant be -value

austinl · Answer

I got -75.8176, and you can indeed get a negative degree. It just means that it went around the unit circle in the opposite direction.

anonymous · Answer

but the answer is 172.8 and 352.8

austinl · Answer

Apologies, I got -73.8158.

austinl · Answer

I'm not sure then. Sorry I couldn't be of more help.