Evaluate 4 over 7 - 7 over 15 + 1 over 3
confusing or not, that is what you have to do
These are fractions
yeah i know lets take them one at a time
\[\frac{4}{7}-\frac{7}{15}\] is the first one
Ops the first one is 4/5
4/5 - 7/15 + 1/3 ?
Yaa
then it is easier
Be right back sorry
It's so simple.. 4/5 = 12/15 ? Understood. 1/3 = 5/15 ?understood. The answer is 12/15+5/15 - 7/15 = 10/15 = 2/3
I don't get it @vipvipindev
Understood 4/5 = 12/15 ?
Noo
How.... it is bc you simply that to get 4/5
4/5 *3/3=12/15
For addition we require a need to make the denominator same. So by multiplying 5 with 3 we get it as 15. When we multiply to denominator we also do it for numerator. Understood?
Ohokkk yes
Sameway did here : 1/3* 5/5 ?
\[\frac{ 4 }{ 7 }-\frac{7}{15}+\frac{1}{3}\] Find the common factor of the denominators: 7: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98, 105 15: 15, 30, 45, 60, 75, 90, 105 3: 3, 6, 9, 12, 15, ... , 105 (because 3 x 35 = 105) Multiply the fractions to make the numerator the same as the common factor: \[\frac{ 4 }{ 7} * 15 = \frac{ 60 }{ 105 }\] \[\frac{ 7 }{ 15} * 7 = \frac{ 49 }{ 105 }\] \[\frac{ 1 }{ 3} * 35 = \frac{ 35 }{ 105 }\] Lastly, add/subtract the fractions with the same denominator: \[\frac{ 60 }{105}-\frac{49}{105}+\frac{35}{105} =\frac{46}{105}\]
So u have to get he the nominator to all be the same
Denominator **
Yes that is correct
Argilly showed the whole process for the problem as originally posted
But it says the answer is 2/3
Key is to find the common denominator. One way is to just multiply all of the denominators together. This works, but gives a bigger number than neede if one denominators is a multiple of another.
I think it's better to give 15 as a common denominator so that he/she can understand!@whpalmer4
Ohokkkkkk I get it now ... but vipvipindev if e denominator is 15 how did u get 3
\[\frac{4}{5}-\frac{7}{15}+\frac{1}{3}=\frac{4*3}{5*3}-\frac{7}{15}+\frac{1*5}{3*5}=\frac{12-7+5}{15}=\frac{10}{15}=\frac{2*5}{3*5}=\frac{2}{3}\]
@vip hadn't finished yet, doing latex on iPad keyboard while walking is very slow...
You can also find least common multiple to use as common denominator by making lists of multiples to see which comes up first: 3 6 9 12 15 5 10 15 15 15 is first number to appear in all 3 lists so it is least common multiple of 3,5,15
Ohhh okk I see now...thanks you
Can also do it by factoring denominators and combining 3 factors to 3 5 factors to 5 15 factors to 3*5 We multiply each unique factor found, using as many copies found in the number that had the most. Here that would be 3*5=15
I get it now wow that was easy now that I noe it
If doing problem with different denominators of 2 8 12 (for example only) 2: 2 8: 2*2*2 12:2*2*3 Here we multiply 2*2*2*3=24 because 2 and 3 were factors found and we had 3 2s in factors for 8 2 4 6 8 10 12 14 16 18 20 22 24 8 16 24 12 24 Again 24 is first number in each list so it is least common multiple of 2,8,12 This example shows how just multiplying denominators together may give unnecessarily large denominator: 2*8*12=192 which is 8x as big as needed!
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