A ball is dropped from the top of a 1,000 foot building. The height of the ball is half its original height after each bounce.
Part 1: What will the height of the ball be after 9 bounces?
Part 2: Using complete sentences, explain the procedure taken to answer this question.
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OpenStudy (anonymous):
almost same lol as last one.
OpenStudy (anonymous):
I know but I can't plug everything in for some reason
OpenStudy (anonymous):
just remember
ar^0 + ar^1 + ar^2 ...
0 1st 2nd ... bounce
^ here we start at 0 instead of 1 cuzz the ball hasn't bounced yet.
1000 +500+250 <- cuzz of the half with me so far?
OpenStudy (anonymous):
69
OpenStudy (anonymous):
tim086m your a virgin aren't you... lol
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OpenStudy (anonymous):
512000?
OpenStudy (anonymous):
no i did it wrong let me recheck
OpenStudy (anonymous):
okayy
OpenStudy (anonymous):
the 9th bounce should be
ar^9
but before we deal with that lets look at what we do know
a=1000
ar^1=ar=500 So we plug in the a and solve for r
1000*r=500
r=500/1000 = 1/2 HERE WHERE I WENT WRONG LAST TIME
So we know
a=1000
r=1/2
so we get ar^9 and plug in
1000*.5^9= answer :)
OpenStudy (anonymous):
1.953125 ?
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OpenStudy (anonymous):
last time i went
r=1000/500=2 :P lol it was reverse order.
and yes that looks right LB :)
OpenStudy (anonymous):
@blow-some-smoke-420 how you get 69? are you sure? :(
OpenStudy (anonymous):
thankyouuu(:
OpenStudy (anonymous):
im think so why what did u get
OpenStudy (anonymous):
1.953125
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