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Mathematics 16 Online
OpenStudy (anonymous):

Can someone tell my whether this result are correct or not?

OpenStudy (anonymous):

\[\int\limits_{1}^{2}\frac{ dx }{ \sqrt{x^2-1} }=acosh(2)\]

OpenStudy (anonymous):

\[\lim_{n \rightarrow 1^+}\int\limits_{1}^{2}\frac{ dx }{ \sqrt{x^2-1} }=\lim_{n \rightarrow 1^+}\left[ acosh \right]^{2}_{n}=\lim_{n \rightarrow 1^+}acosh(2)-acosh(n)=acosh(2)\]

OpenStudy (loser66):

how can you get it?

OpenStudy (anonymous):

Let \[f(x)=\frac{ 1 }{ \sqrt{x^2-1} }\] then \[f'(x)=acosh(x)\]

OpenStudy (anonymous):

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