Question

What is the vertex for the function? (You will want to find the axis of symmetry first.) Write as an ordered pair, leaving no spaces, such as (1,-4).
y = -3x2 + 6x

Answer 1

@Luigi0210 @mathstudent55 @thomaster

Answer 2

@shkrina

Answer 3

do u have any guess ..

Answer 4

idk how to find the axis of symmetry so no

Answer 5

http://openstudy.com/study#/updates/4f57de86e4b0c9fd2d4b7d90

check this out .... its explained here

Answer 6

@amistre64

Answer 7

u did not get that its same sum ...

Answer 8

anyways @amistre64

Answer 9

it didnt make sense

Answer 10

given: ax^2+bx+c

the vertex is on the axis of symmetry: -b/2a

when x= -b/2a we find y

main points ,,,

Answer 11

given the format: y = ax^2 + bx + c, the axis of symmetry that they vertex lives on is the value of -b/(2a)

y = ax^2 + bx + c
y = -3x^2 + 6x + 0

a = -3
b = 6 , so we have everything needed to define -b/(2a)

the value of y for the vertex is simply achieved by plugging in the value of x that we determined

Answer 12

OR, another method is to comlete the square to rewrite this into vertex form:

y = m(x-a)^2 - b such that the vertext is (a,b)

Answer 13

okay

Answer 14

so the answer is (-3,6) ?

Answer 15

y = -3x^2 + 6x

y = -3( x^2 -2x)

y = -3( x^2 -2x +1 -1)

y = -3( x^2 -2x +1) + 3

y = -3(x-1)^2 + 3

Answer 16

okay so is the answer (-3,6)

Answer 17

no

Answer 18

-__- i suck at math

Answer 19

y = ax^2 + bx + c
y = -3x^2 + 6x + 0

a = -3
b = 6 , so we have everything needed to define -b/(2a)

x = -6/(2*-3) = 1

Answer 20

so what do i need to do to get the answer!!

Answer 21

well, from what has been posted so far; we determined that x=1, solve for y when x=1

y = -3(1)^2 + 6(1)
= -3 + 6

Answer 22

so y = 3 ?

Answer 23

so its (1,3)

Answer 24

that does seem to be correct yes :)

Answer 25

alright thanks!!

Answer 26

The parabola for the function will point in which direction? y = x2 + 3x - 4

Answer 27

last question

Answer 28

"point" ?

Answer 29

upward or downward

Answer 30

since the x^2 term has a positive coefficient, it will have the same form as y = x^2

Answer 31

so upward?

Answer 32

y = x^2 looks like a "U", so it opens upwards. if I were to take an educated guess, id assume they are thinking that it "points" downward like a "V"

Answer 33

oh alright thanks again!

Answer 34

good luck