A particle is moving around in a circle and its position is given in polar coordinates as x = Rcosθ, and y = Rsinθ, where R is the radius of the circle, and θ is in radians. From these equations derive the equation for centripetal acceleration.
|dw:1372829534069:dw| Your motion has been shown in the figure. I have assumed that motion started from (R,0). Although result will be same if you choose any other initial position.ω is the angular velocity. So, θ =ωt in time t position vector at any time,t is therefore given by r=Rcosωt i +Rsinωt j i and j are unit vectors along x and y axis respectively. Differentiating twice , will gives us acceleration a=-ω^2r You can verify this yourself by differentiation. Since there is no other acceleration ,this being uniform circular motion.This total acceleration is equal to centripetal acceleration.
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