Mathematics
16 Online
OpenStudy (anonymous):
If the shaded area region is A, estimate the value of the integral.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\int\limits_{-1.5}^{4} f(x)dx\]
OpenStudy (anonymous):
OpenStudy (anonymous):
Above is the image of the graph.
OpenStudy (amistre64):
i would estimate a quadratic
OpenStudy (amistre64):
f(x) = k(3-x)(5-x)
such that f(4) = -1
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So then I should figure out what k is?
OpenStudy (amistre64):
of course, since there are an infinite number of quadratics with those roots
k(3-4)(5-4) = -1
k(-1)(1) = -1, k = 1
OpenStudy (anonymous):
Okay, and now how would I put that into the inergral?
OpenStudy (anonymous):
*integral
OpenStudy (amistre64):
define f(x) for that piece as: (3-x)(5-x) and integrate the poly
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
from 3 to 5 that is
OpenStudy (anonymous):
Okay.
So then I have -2+2+((3-5)(5-5)-(3-3(5-3))
OpenStudy (amistre64):
or the same area can be had from: x(2-x)
OpenStudy (amistre64):
from 0 to 2
OpenStudy (amistre64):
well, -x(2-x)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I am seeing zero as an answer.
OpenStudy (amistre64):
x^2 - 2x, integrates to:
x^3/3 - x^2; at x=2 we have
8/3 - 4
(8-12)/3
OpenStudy (anonymous):
I'm sorry. I'm a little lost.
Could you help me set up the entire integration over the interval?
OpenStudy (amistre64):
|dw:1372788718308:dw|