Complete the table for the function and find the indicated limit.
\[\lim_{x \rightarrow 0} \frac{ x^2 }{ \sin x }\]
A. -0.0300, -0.0200, -0.0100, 0.0100, 0.0200, 0.0300 limit = -1 B. -0.0300, -0.0200, -0.0100, 0.0100, 0.0200, 0.0300 limit = 0 C. -0.0300, -0.0200, -0.0100, 0.0100, 0.0200, 0.0300 limit = 0.1 D. -0.0300, -0.0200, -0.0100, 0.0100, 0.0200, 0.0300 limit = 1
Would the answer be B? Isn't it discontinuous?
im sorry I have no idea :(
so, what values did you get for the table?
they should match one of the choices I'd think
How would you begin this problem? Would you first substitute for 0?
well, you simply finish up the table :)
you have an "x" atop, just get the f(x)
And how do you find the limit exactly? I'm sorry, I'm just really bad at this.
well, what values did you get?
the limit is just where f(x) is moving towards
lemme give you a quick table so you can see say $$ \begin{matrix} x&&y \\ hline\\ 2.3&& 6\\ 2.4&& 7\\ 2.5&& 8\\ 2.8&& 9\\ \color{blue}{3}&& \color{blue}{10}\\ 3.7&& 14\\ 3.6&& 13\\ 3.5&& 12\\ \end{matrix} $$
so, as you can see, as "x" is one value, f(x) or "y", takes on whatever value as x -> 3 y goes to 10 or as "x" goes to 3, the limit of "y" is 10
on the example above, "x" takes on values "before" and "after" 3 and notice how "y" is ever growing towards, or shrinking towards, 10
$$ \begin{matrix} x&&y \\ \hline\\ 2.3&& 6\\ 2.4&& 7\\ 2.5&& 8\\ 2.8&& 9\\ \color{red}{3}&& \color{red}{10}\\ 3.5&& 12\\ 3.6&& 13\\ 3.7&& 14\\ 3.8&& 15 \end{matrix} $$
like so
I kind of get it, I think. Well, your example at least
your exercise is exactly the same, just different values
so let's do the table let's see, lemme fire up my calculator
I think it is B because the values are getting closer and closer to zero
so I get -0.03000450047254484 -0.02000133339555818 -0.01000016666861113 0.01000016666861113 0.02000133339555818 0.03000450047254484
Yes I got those values
so the function looks like|dw:1372792861365:dw| so yes, is approaching 0
thus the liimit is 0
Thanks so much!
yw
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