Question

Rewrite as a logarithmic equation. e^(4)=y

Answer 1

$$\large {
a^x = \color{red}{y}\\
log_a\color{red}{y} =x
}
$$

Answer 2

@jdoe0001 , thank you, but can you help me a little further on the steps?

Answer 3

what steps?

Answer 4

@reemii for writing the e^4=y as a logarithmic I don't get the process he gave me.

Answer 5

the definition of the logarithm is \(\log_a x=y\) if and only if \(x=a^y\).

if you see \(e^4=y\), you will apply a logarithm on both sides. there is a choice left to you, that is the choice of the "base" , the number \(a\) in the line above. Since you see \(e^4\), you choose \(a=e\), then you apply \(\log_e\) on both sides.
(\(\log_ex=\ln x\))

Answer 6

LHS: \(\log_e (e^4) = 4\) (have you seen that?)
RHS: \(\log_e y\) .. nothing else to say about it.

Answer 7

@_xcrvnts
equation is \(4=\log_e y\). (=\(\ln y\))