the shape of f(x)=1/5x^5, but moved 3 units to the the left and 3 units down. A) g(x)=-1/5(x+3)^5-3 B) g(x)=1/5(x-3)^5-3 C) g(x)=1/5(x-3)^5+3 D) g(x)=1/5(x+3)^5-3
usually $$\huge { f(x) = A(x\pm B)\pm C\\ } $$ B = horizontal shift C = vertical shift
and +B for 'left' -B for 'right' +C for 'upward' -C for 'Downwards'
so it would be D/
yup
D) shows ---> (x+3)^5-3 that'd be a horizontal shift to the right, and vertical down
ohh, maybe not
rigth, is shifting to the left
oh sorry I messed up it should be +B for right and -B for left
nope, you're correct, + moves it to the left
so it's D
no @jdoe0001 it should be B x decreases as we move left from origin (0,0) visualize a number line and you will understand
is actually backwards, and a bit off, but +B moves the graph to the left, and -B will move it to the right
I mean, that doesn't hold true on many cases, like in trig, but it does for this translations
I'm not even quite sure about trig, but I could test really quick
nope, the same shift behaviour is also true in trig
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