Question

M → M+ + e-

Is M an oxidizing or reducing agent?

Answer 1

there is not enough information. reducing/oxidizing agents are relative to another and there is only one species here.

Answer 2

that's all it gave me

Answer 3

that doesn't make sense.. was there a question previous to it?

M → M+ + e-
^ ^
neutral form oxidized form

Answer 4

M → M+ + e-

Is M an oxidizing or reducing agent? only this one nothing elese

Answer 5

well the oxidizing/reducing nature of each species is relative to what it's reacting with, some will be oxidized some reduced.

M would be the reduced form so i would say it's the reducing agent (because it's likely to give electrons (since it's not deficient)).

M+ is e deficient, so it will more likely oxidize other species.

Answer 6

okayy thanks man one last question if you don't mind

Which of the following statements is true of cations?

Cations are attracted to the anode.
Cations undergo oxidation at the proper electrode.
Cations undergo reduction at the proper electrode.
Cations are negatively charged.

Answer 7

have you studied galvanic cells?

Answer 8

haha. i don't know what that is -__-

Answer 9

lol we'll you should, it's kinda impossible to answer these questions if you don't know what they're talking about. This pretty much sums it up

Answer 10

i like pictures more than words thanks

Answer 11

this is whats happening at the left electrode : M → M+ + e-

this is whats happening at the right electrode: M+ + e-→ M

Answer 12

Because of OIL RIG, M lost one electron, it's oxidized, so its a reducing agent.