The figure below shows a circle with center O. Segment PQ is tangent to the circle at P and segment RQ is a tangent to the circle at R.
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
Which statement and reason is most appropriate for box 3?
OpenStudy (anonymous):
Segment OP is congruent to segment OR since they are congruent chords.
Angle OPQ is congruent to angle ORQ since they are corresponding sides of congruent triangles.
Segment OQ is congruent to segment OQ by the reflexive property of line segments.
Angle OPQ is congruent to angle ORQ since they are vertical angles.
OpenStudy (anonymous):
@jim_thompson5910 May you please help me?
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jimthompson5910 (jim_thompson5910):
Segment OP is congruent to segment OR since they are congruent chords
is false because they are radii (not chords)
they are congruent though
OpenStudy (compassionate):
@jim_thompson5910 , any reason I'm blocked?
jimthompson5910 (jim_thompson5910):
Angle OPQ is congruent to angle ORQ since they are corresponding sides of congruent triangles.
that's partially true as well: they are congruent, but NOT for this reason (besides this was already proven)
OpenStudy (anonymous):
I was thinking that it was the third choice
OpenStudy (anonymous):
However I am not very good at proofs and I am not entirely sure
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jimthompson5910 (jim_thompson5910):
you are correct A$apGeometryQuestions
that's a true statement and it's useful in this case
OpenStudy (anonymous):
Thank you so much for validating for me! @jim_thompson5910
OpenStudy (anonymous):
You get a medal.
jimthompson5910 (jim_thompson5910):
and Compassionate, I'm not sure how you got blocked
I may have blocked you a long time ago (don't remember doing so though)
I'll unblock you
jimthompson5910 (jim_thompson5910):
yw
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OpenStudy (anonymous):
May you aid me with one last question please? @jim_thompson5910
jimthompson5910 (jim_thompson5910):
ok
OpenStudy (anonymous):
Give me some time to post it please. Maybe a minute.
OpenStudy (anonymous):
Look at the figure shown below
OpenStudy (anonymous):
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OpenStudy (anonymous):
A student made the table below to show the steps to prove that DC is equal to EC.
jimthompson5910 (jim_thompson5910):
post a screenshot of the table
OpenStudy (anonymous):
OpenStudy (anonymous):
Here it is
OpenStudy (anonymous):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
ok notice how lines 4 and 6 have the same right side (after the equals sign)
jimthompson5910 (jim_thompson5910):
what does that mean? what does that allow us to say?
OpenStudy (anonymous):
They are supplementary angles?
jimthompson5910 (jim_thompson5910):
no, nowhere does it say they add to 180
OpenStudy (anonymous):
well the picture slightly suggests it, but I have no idea
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jimthompson5910 (jim_thompson5910):
this is a very counter-intuitive idea...but NEVER base any decisions solely on the drawing alone
jimthompson5910 (jim_thompson5910):
the drawing may not be to scale
OpenStudy (anonymous):
Yes, I understand; My fault.
jimthompson5910 (jim_thompson5910):
no worries
OpenStudy (anonymous):
they are corresponding? no?
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OpenStudy (anonymous):
ACD and DCE
jimthompson5910 (jim_thompson5910):
ACE and BCD are equal to the same thing, so they must be ______
OpenStudy (anonymous):
congruent/vertical?
jimthompson5910 (jim_thompson5910):
let x = m<ACD + m<DCE
OpenStudy (anonymous):
ok
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jimthompson5910 (jim_thompson5910):
so we can say that m<ACE = x and m<BCD = x
jimthompson5910 (jim_thompson5910):
I'm just going to lines 4 and 6 and replacing m<ACD + m<DCE with x
OpenStudy (anonymous):
This is true
OpenStudy (anonymous):
m<ACD + m<DCE=x
jimthompson5910 (jim_thompson5910):
yep
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OpenStudy (anonymous):
got it. Next step?
jimthompson5910 (jim_thompson5910):
so if m<ACE = x and m<BCD = x, then what's their relationship?
OpenStudy (anonymous):
they are congruent angles
jimthompson5910 (jim_thompson5910):
yep
jimthompson5910 (jim_thompson5910):
so their angle measures are equal
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OpenStudy (anonymous):
this is because both m∡ACD + m∡DCE equals them
OpenStudy (anonymous):
and yes
jimthompson5910 (jim_thompson5910):
so m<ACE = m<BCD
jimthompson5910 (jim_thompson5910):
the reason is ______
OpenStudy (anonymous):
their angle measures are equal
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OpenStudy (anonymous):
I'm not sure which postulate I would use to prove it
jimthompson5910 (jim_thompson5910):
well if x = y and x = z, then y = z
what property are we using?
OpenStudy (anonymous):
addition property of equality
jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
Transitive property of equality
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OpenStudy (anonymous):
Im almost sure @jim_thompson5910
jimthompson5910 (jim_thompson5910):
closer, but no
OpenStudy (anonymous):
Last option: substitution property of equality, but I doubt it. :S
jimthompson5910 (jim_thompson5910):
well I would just say substitution
jimthompson5910 (jim_thompson5910):
the transitive property is the idea that if x = y and y = z, then x = z
so it's very similar
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OpenStudy (anonymous):
Ok.
jimthompson5910 (jim_thompson5910):
substitution is the same idea basically
OpenStudy (anonymous):
Yes, it is formally suggested as substitution property of equality in my class,
jimthompson5910 (jim_thompson5910):
I don't think there's a "substitution property of equality" though
it's just known as "substitution"
jimthompson5910 (jim_thompson5910):
hmm I guess "substitution property of equality" is a bit valid since it deals with equations
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OpenStudy (anonymous):
Yep, It doesn't really make a difference though. It's ok, either way.
jimthompson5910 (jim_thompson5910):
yeah you could argue either way really
OpenStudy (anonymous):
exactly. So would that be the justification used for the answer? "substitution"
jimthompson5910 (jim_thompson5910):
yeah that's what I would ultimately go with: it's short and simple
OpenStudy (anonymous):
So the final answer is: m<ACE = m<BCD ----> substitution
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OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
yep
OpenStudy (anonymous):
I dont get why the proof would not work without that step
jimthompson5910 (jim_thompson5910):
if I were grading this, I'd say it's correct
then again, the teacher may be looking for "substitution property of equality" or "Transitive property of equality"
but you could argue for either one really
jimthompson5910 (jim_thompson5910):
well look at the next line
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jimthompson5910 (jim_thompson5910):
what is that line
OpenStudy (anonymous):
The ASA pos. is saying that the two triangles are congruent
jimthompson5910 (jim_thompson5910):
ok what does ASA stand for
OpenStudy (anonymous):
Angle-side angle
jimthompson5910 (jim_thompson5910):
ok so you need a pair of angles congruent
and you need a pair of sides congruent
the sides are between the angles
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jimthompson5910 (jim_thompson5910):
line 1 gives you the sides
line 2 gives you one pair of the angles
but which line gives you the other pair of angles?
OpenStudy (anonymous):
the line we just solved
OpenStudy (anonymous):
line 3 also does too i think
OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
line 3 does not
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jimthompson5910 (jim_thompson5910):
if it did, why did we do all that work after line 3?
jimthompson5910 (jim_thompson5910):
line 6 does though, that's the missing piece of info to complete and set up ASA
OpenStudy (anonymous):
Oh snap lol. I'm foolish. So we then would have all angle measures