Question

What is the equation of a circle with center (3,8) and radius 2?

Answer 1

(x-a)^2+(y-b)^2=r^2
(a,b) is the center.

Answer 2

\[\bf (x-a)^2+(x-b)^2=r^2\]Where \(\bf (a,b)\) is the centre of the circle and \(\bf r\) is the radius.

@K_saunders4

Answer 3

Sorry, it should be \(\bf (y-b)^2\). My apologies.

Answer 4

\[\bf (x-a)^2+(y-b)^2=r^2\]

Answer 5

so the answer is (x-3)^2+(y-8)^2=2

Answer 6

Thanks so much guys

Answer 7

idk I have options here a-d and none of them says that

Answer 8

r^2 is 4, not 2

Answer 9

A. (X-3)^2+(y-8)^2=4, B. (x+3)^2+(y+8)^2=4 or C. (x+3)^2+(y+8)^2=2 or D. (x-3)^2+(y-8)^2=2 which one?

Answer 10

a) loolololol

Answer 11

So a?

Answer 12

Lol sorry and okay thanks so much