If the hydrogen ion concentration is 10-7M, what is the pH of the solution? Show all work.
\(\large pH = -log[H^+]\)
I understand that much, but don't know where to plug the numbers in.
Well your \(\large [H^+]\) is the hydrogen ion concentration. I'm not sure if the one given in your question is correct. Should it be \(\sf 10*10^{-7}~?\)
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That's all the question says is 10 to the negative 7th power.
Just \(\Large 10^{-7}M\) ??
Yes
Oke then plug that in the formula \(\large pH = -log[H^+]\)
So \(\large pH = -log[10^{-7}]\)
I'm totally lost with this question lol
Where are you lost? the only thing you have to do is calculate \(\large -log[10^{-7}]\)
what does -log equal though?
log is a function on your calculator. just put a - in front So enter: -log(10^-7)
I don't have a calculator.
Then go to www.google.com and enter -log(10^-7)
google has a calculator
One minute.
answer of 7?
so pH = 7?
yes that is correct :)
thank you!
No problem :)
pH of 10^-7 M HCl = 7 then the pH of 10^-8 M HCl comes out to be 8. which is wrong. think of it this way. you added small amount of acid into water, and still the solution remained neutral or turned basic if conc of acid = 10^-8?? adding an acid can never make water basic or neutral. use this link to teach yourself as to how to proceed for the solution to this question, and if you face any difficulty, just ask. http://www.faculty.umassd.edu/michele.mandrioli/172cbook/fCHM2.D.2.html
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